SOLUTION: Factor by grouping: 3b^2+16b+5 I am having a very hard time with this. Is there any trick or hints you can provide?

Question 70783: Factor by grouping:
3b^2+16b+5
I am having a very hard time with this. Is there any trick or hints you can provide?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factor by grouping:
3b^2+16b+5
--------------
Think of two numbers whose product is 3*5=15
and whose sum is 16
------------
The numbers are 1 and 15
-----------
Replace 16b in the problem with b+15b to get:
3b^2+b+15b+5
Factor the 1st two terms and the last two terms separately:
b(3b+1) + 5(3b+1)
Factor out the common factor of (3b+1) to get:
(3b+1)(b+5
Those are the factors you want.
This method is called the AC method because you wanted to find
two numbers whose product was AC=3*5=15.
Cheers,
Stan H.
RELATED QUESTIONS
Can you please help me with this problem I am having a very hard time with it. The... (answered by Earlsdon)

I am having a hard time with this problem!!! HELP PLEASE!! -3a^2b/35a^5 multiplied by... (answered by rchill)

I am having a very difficult time solving this quatratic equation, any help you can... (answered by tutor_paul)

I am having a hard time with Variation, Progression, and Theorems. My question is What is (answered by longjonsilver)

I am having trouble with this problem. Can you help me please? Factor by grouping... (answered by jim_thompson5910,checkley71)

I am having a hard time with this problem. I need to factor the following:... (answered by rothauserc)

I am really having a hard time with these two problems. I'm not good at math to begin... (answered by rfer)

Here is the question on my quiz sheet- Find the slopes of the lines that are (a)... (answered by elima)

I am having a very hard time trying to figure this out. Can you please help me? Find... (answered by Fombitz)