SOLUTION: Factor completely:
b^2 - ab - 6a^2
Would the answer be:
(b-6a)(b+a)?? Thank you
Algebra.Com
Question 70364: Factor completely:
b^2 - ab - 6a^2
Would the answer be:
(b-6a)(b+a)?? Thank you
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Factor completely:
b^2 - ab - 6a^2
(b___a)(b___a)
You need to fill the blanks with two inegers that multiply to give you the last term, -6, but add together to give you the middle coefficient, -1.\
2*(-3)=-6 and 2+(-3)=-1
To check your answer FOIL it back out to see if you get what you started out with:
(b+2a)(b-3a)
b(b-3a)+2a(b-3a)
b(b)+b(-3a)+2a(b)+2a(-3a)
b^2-3ab+2ab-6a^2
b^2-ab-6a^2 We're right!!!
Happy Calculating!!!!
RELATED QUESTIONS
Factor completely. b^2 – ab –... (answered by Earlsdon)
Factor completely... (answered by malakumar_kos@yahoo.com)
Factor completely... (answered by tutorcecilia)
factor completely.... (answered by scott8148)
Factor completely.
b^2 – ab – 6a^2
I got this answer this time is it right?
(b –... (answered by stanbon)
Factor completely: b^2-ab-6a^2
(a)(b+3a)(b-2a)
(b)(b+6a)(b-a)
(c)(b-3a)(b+2a)... (answered by bucky)
Factor completely. b^2-ab-6a^2
Please assist me with this.
Thanks (answered by checkley71)
ab+b^2
-------
4ab^5
------
a+b
----
6a^2b^4
Thank you for all your... (answered by RAY100)