# SOLUTION: A poster has a length 4 inches greather than its width w. Demetrius will place a frame 2 inches wide around the poster. The area of the poster and frame together is 672 square inch

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: A poster has a length 4 inches greather than its width w. Demetrius will place a frame 2 inches wide around the poster. The area of the poster and frame together is 672 square inch      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Distributive, associative, commutative properties, FOIL Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Distributive-associative-commutative-properties Question 66106: A poster has a length 4 inches greather than its width w. Demetrius will place a frame 2 inches wide around the poster. The area of the poster and frame together is 672 square inches. Which factored equation could be used to find the width of the poster? Answer Choices: A (w+30)(w-20)=0 B (w+4)(w+8)=0 C (w+2)(w+6)=672 D (w-32)(w+20)=0Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!Let's find the equation for the area of the poster + frame. The area of the poster alone is: but the total size with the frame is 4 inches more on each side, so the area then becomes: and since the length, L = W+4, you can substiute this to get: and the total area is given as 672 sq.in, so... Simplifying this, you get: Now subtract 672 from both sides. Now that we have the quadratic equation, we can factor it, if possible: so: This does not match exactly any of the given possible answers, does it?