SOLUTION: Integer Operations and Order of Operations 7+{6-4[5-2(4+5)]+3} please show me the steps.
Algebra.Com
Question 601270: Integer Operations and Order of Operations 7+{6-4[5-2(4+5)]+3} please show me the steps.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
7+{6-4[5-2(4+5)]+3}
7+{6-4[5-2(9)]+3}
7+{6-4[5-18]+3}
7+{6-4[-13]+3}
7+{6+52+3}
7+{61}
7+61
68
So 7+{6-4[5-2(4+5)]+3} = 68
RELATED QUESTIONS
performing the operations and simplifying, please show steps so that I may use for... (answered by MathLover1,AnlytcPhil,Edwin McCravy)
Using order of operations, simplify... (answered by josgarithmetic)
please solve and show order of operations
(–16 ÷ 2) × 4 – 3 +... (answered by Stitch)
3(6+7) IS ORDER OF OPERATIONS \PLEASE HELP ME (answered by solver91311)
Order of Operations:
390 ÷ [5(7 +... (answered by farohw)
Order of Operations:
6 + 4²
----------
3² · 4
(answered by MathLover1)
Order of Operations:
4[12 ÷ (6 -... (answered by farohw)
I am having difficulty with this problem and the order of the operations: (16)/(-2)^3 -... (answered by CubeyThePenguin)
Order of operations with equations
-4(2x – 3) = -8x + 5
(answered by checkley71)