SOLUTION: Please help w/ the following:
[{6x^2-1/4}^2}]
Thank you.
Algebra.Com
Question 55451: Please help w/ the following:
[{6x^2-1/4}^2}]
Thank you.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
{6x^2-1/4}^2}
= 36x^4 - 2(6x^2)(1/4)+(1/16)
= 36x^4 - 3x^2 + (1/16)
Cheers,
Stan H.
RELATED QUESTIONS
Find each of the following squares.
(w - 1/4)^2
please help.
Thank... (answered by sdmmadam@yahoo.com)
Please help me solve the following equations:
50) a+4/2 = a+4/a
64) 4w-1/3w+6 - (answered by madhujiithcharu@yahoo.co.in)
Please help w/ the following:
Solve
x^2/2 - 5x/4 = -3/4
Thank... (answered by funmath)
Please help w/ the following:
Solve
x+2/3 - x-2/5 =4
Thank... (answered by Earlsdon)
Please help w/ the following:
2x^-2+3x^-1+1=0
Thank... (answered by funmath)
Please help w/ the following:
Factor:
2x^4+7x^3-29x^2-112x-48
Thank You.
(answered by stanbon)
Please help simplify the following:
((6x^2)/ (x^2+2x+4))/ ((x^3-8) /(-6x+12))
Thank... (answered by Boreal,MathTherapy)
Please help. Thank you in advance
Determine whether the vectors v and w are parallel... (answered by Fombitz)
Please help w/ the following:
Solve(3x+3)^2=16
Thank... (answered by funmath)