SOLUTION: Hope I am in the right place with this question. Factor each of the following trinomials completely. 2a^3-52a^2b+96ab^2. I got as far as ... 2a(a^2-26ab+48b^2). Then I

Question 54535This question is from textbook Beginning Algebra
: Hope I am in the right place with this question.
Factor each of the following trinomials completely.
2a^3-52a^2b+96ab^2.
I got as far as ...
2a(a^2-26ab+48b^2). Then I got completely lost. This question is from textbook Beginning Algebra

Found 3 solutions by Nate, Earlsdon, funmath:
Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
2a(a^2 - 26ab + 48b^2) factors of 48 that sum to -26 ~> -2 and -24
2a(a - 2b)(a - 24b)
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Ok, your first step is fine.
Now you can factor the parentheses:
...and you're done!
Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!
You got the first step right.

and so...

Two numbers that multiply together to give you +48, but add together to give you -26 are -2 and -24.

Happy Calculating!!!
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