SOLUTION: I have a problem with an equation. 4/z-1 - 2/z+1 the answer is 2z+6/(z-1)(z+1) My question is how do you get that answer? Any help at all would be very appreciated! Than

Algebra.Com
Question 52727: I have a problem with an equation.
4/z-1 - 2/z+1 the answer is 2z+6/(z-1)(z+1) My question is how do you get that answer?
Any help at all would be very appreciated!
Thank you :o)

Answer by rchill(405)   (Show Source): You can put this solution on YOUR website!
You need to have a common denominator for both fractions; hence, the common denominator of . So using this common denominator, we need to determine what each of the fractions is with that common denominator. The first fraction becomes , which simplifies to . The second fraction becomes , which simplifies to . Now, we have the , which simplifies to . Now combining like terms we get .
RELATED QUESTIONS

z^(4)-z^(2)-2z+2 Please could someone help me with the last part of this question.... (answered by josgarithmetic)
Factor Completely. 6z^3-27z^2+12z I came up with a completely different answer than... (answered by bucky)
Hi, I hope I am submitting this problem under the right section, the chapter I'm... (answered by edjones)
Factorise each of the following over C a) f(z)=z^3+z^2+2z-4 b)g(z)= z^3+(2-i)z^2-z-2+i (answered by solver91311)
I am working on distributive property. This is the only question I can not figure out on... (answered by ewatrrr,josgarithmetic,Fombitz)
I have to solve for 'z' z/(z-2) - 1/(z+5) = 7/z^2+3z-10 Now I know that I have to... (answered by richwmiller)
Hello! I'm having problems with substitution and for the following problem i keep getting (answered by stanbon)
Can you please help me solve this question? Many of the terms have a # or a letter with... (answered by KMST)
Question : simplify : x-[x-(y-z)]-z My work: -1(y-z) (answered by Edwin McCravy,mccravyedwin)