SOLUTION: How do you solve for 6x^3=3x^2+3x

Question 526391: How do you solve for 6x^3=3x^2+3x

Found 2 solutions by jim_thompson5910, oberobic:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

6x^3=3x^2+3x

6x^3-3x^2-3x=0

3x(2x^2-x-1)=0

3x(x-1)(2x+1)=0

3x=0 or x-1=0 or 2x+1=0

3x=0 or x=1 or 2x=-1

x=0/3 or x=1 or x=-1/2

x=0 or x=1 or x=-1/2

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
6x^3 = 3x^2 + 3x
6x^3 - 3x^2 -3x = 0
3x*(2x^2 -x -1) = 0
3x*(2x+1)(x-1) = 0
.
x = 0, -1/2, 1
.

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