SOLUTION: physics: an object is released from a plane at an altitude of 1600 ft. the initial velocity is 0ft/s. how many seconds will the object hit the ground? d=vt+16t^2 is the form

Question 47013: physics:
an object is released from a plane at an altitude of 1600 ft.
the initial velocity is 0ft/s. how many seconds will the object hit the ground?
d=vt+16t^2 is the formula but I'm just not seeing where this is supposed to all come together. my guess is that it will fall very darn fast.
Found 2 solutions by venugopalramana, Nate:
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
an object is released from a plane at an altitude of 1600 ft.
the initial velocity is 0ft/s. how many seconds will the object hit the ground?
d=vt+16t^2 is the formula but I'm just not seeing where this is supposed to all come together. my guess is that it will fall very darn fast.
D=1600...V=0
1600=0*T+16*T^2
T^2=1600/16=100
T=10 SEC.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
The formulas I work with look like this:

t = 10 seconds
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