SOLUTION: Simplify [(3x^2y^0)^2+1/x^-1](2x+5). Assume that no variable equals 0.
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Question 464875: Simplify [(3x^2y^0)^2+1/x^-1](2x+5). Assume that no variable equals 0.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Simplify [(3x^2y^0)^2+1/x^-1](2x+5).
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= [(3x^2)^2+1/x^-1](2x+5)
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= [(9x^4) + x](2x+5)
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= (9x^4+x)(2x+5)
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= 18x^5+45x^4+2x^2+5x
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Cheers,
Stan H.
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