SOLUTION: Factor the expression:
(x-1)^3+1
This is as far as I got:
(x-1) (x-1) (x-1)+1
Then I tried to factor by grouping the four terms
x-1(1) 1(x-1)
I'm lost.
Algebra.Com
Question 458433: Factor the expression:
(x-1)^3+1
This is as far as I got:
(x-1) (x-1) (x-1)+1
Then I tried to factor by grouping the four terms
x-1(1) 1(x-1)
I'm lost.
Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
(x-1)* (x-1) *(x-1)+1
You have to multiply it out all the way and add terms before you can factor
x^3-3x^2+3x
x*(x^2-3x+3)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Factor the expression:
(x-1)^3+1
---------
It's the sum of 2 cubes.
Sub y for x-1
-------
then sub x-1 for y
=
=
RELATED QUESTIONS
Factor x3 + x2 + x + 1 by grouping. What is the resulting expression?
(x2)(x + 1)
(x2 (answered by Fombitz)
Factor x^-1/3 out of x^1/3 + x^-1/3
I multiplied x^1/3 by x^-1/3 and got x^-1 and then... (answered by stanbon)
find all solutions of the equation {{{ 4x-8 sqrt( x )-5=0 }}}.
please show me every... (answered by ewatrrr)
Rewrite the expression
2logx - 3log(x^2+1) +4log(x-1)
as a single logarithm log A. (answered by jim_thompson5910)
this is the equation : x^2-1/2x=1/3
what i have so far is :
x^2-1/2x+1/16=19/48 and i... (answered by stanbon,MathTherapy)
factor by grouping
7x^3-7x^2-x+1
(answered by jim_thompson5910)
Factor by grouping... (answered by stanbon)
Factor by grouping... (answered by mananth)
Factor by grouping... (answered by mananth)