# SOLUTION: I have some factoring problems.. I have solved some, but the others just dont work. 3x(a-3)-5(3-a) I don't even know where to start, it looks factored to me? 20x^2-7x-6. I h

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: I have some factoring problems.. I have solved some, but the others just dont work. 3x(a-3)-5(3-a) I don't even know where to start, it looks factored to me? 20x^2-7x-6. I h      Log On

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 Question 342932: I have some factoring problems.. I have solved some, but the others just dont work. 3x(a-3)-5(3-a) I don't even know where to start, it looks factored to me? 20x^2-7x-6. I have tried about every different combination I can for foil for this one, it just does not work itself out.. It is driving me CRAZY!!! 4x^4 + 12x^3- 28x^2. I don't even know where to start to be honest. Is this a foil problem? Thank you for your time..I can not tell you how valuable this site has been to me.Found 3 solutions by stanbon, nyc_function, akc:Answer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!3x(a-3)-5(3-a) --- 3x(a-3)+5(a-3) --- (a-3)(3x+5) ---------------------------------- 20x^2-7x-6. --- 20x^2-15x+8x-6 --- 5x(4x-3)+2(4x-3) --- (4x-3)(5x+2) ======================== 4x^4 + 12x^3- 28x^2 --------- 4x^2[x^2+3x-7] ================== Cheers, Stan H. ============ Answer by nyc_function(2733)   (Show Source): You can put this solution on YOUR website!The expression 3x(a-3)-5(3-a) becomes 3x(a-3)-5(3-a) after using the distributive rule. 20x^2 - 7x - 6 factors out to be (5x+2)(4x-3). To factor this one, I used the GROUPING METHOD. 4x^4 + 12x^3- 28x^2 factors out to be 4x^2(x^2 + 3x - 7). To factor this one, I needed to do some extra substitutions in terms of letting y = x^2. Done! Answer by akc(7)   (Show Source): You can put this solution on YOUR website!Please post one question is a post. 1. 3x(a-3)-5(3-a) (factorisaton means there should not be + or - between two terms) =3x(a-3)-5(-(a-3)) [-(a-3)= 3-a] =3x (a-3)+ 5 (a-3) [two - equals +] =(a-3)(3x + 5) [taking (a-3) common from both terms] (a-3) & (3x+5) are the factors. . . . . 2. = = = = (4x-3)(5x + 2) (4x-3)&(5x + 2) are the factors . . . . 3. = & are the factors. Again plz ask single question at a time. you can email me for immediate help. my email is akc1@uno.edu