SOLUTION: multiply (-5x^2+4y)(5x^2+5y+z) a. -25x^4-5x^2y^2+20y^2 b. -25x^2-5xy-5x^2z+20y^2+4z c. -25x^4-5x^2y+20y^4-5x^2yz d. -25x^4-5x^2y-5x^2z+20^2+4yz ^means to the power of....than

Question 336030: multiply
(-5x^2+4y)(5x^2+5y+z)
a. -25x^4-5x^2y^2+20y^2
b. -25x^2-5xy-5x^2z+20y^2+4z
c. -25x^4-5x^2y+20y^4-5x^2yz
d. -25x^4-5x^2y-5x^2z+20^2+4yz
^means to the power of....thanks
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression.

Expand.

Distribute.

Multiply.

Now combine like terms.

So expands to .

In other words, .

So the answer looks like it is D) (assuming you forgot the 'y')

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my website.

Jim

RELATED QUESTIONS
(5x^4)(25x^2)^-1 (answered by stanbon)

5x^2-20y^2 (answered by fractalier)

Multiply: (25x^2)/(x^2 - 4) * (x +... (answered by RAY100)

simplify... (answered by jim_thompson5910)

5x-4=25x-6 (answered by Maths68)

25x^2-36/5x+6 (answered by Boreal)

5x^2-25x+20=0 (answered by rothauserc)

factor completely 25x^2 +10x +1 25x^2 +5x +5x +1 (5x +1)(5x... (answered by jim_thompson5910)

625x^4 − 16 factor polynomial completely. (5x-2)(5x+2)(25x-10i)(25x+10i)... (answered by Alan3354,MathTherapy)