SOLUTION: Factor completely thankyou 64a^3-27b^3 a. (4a-3b)(16a^2+9b^2) b. (4a+3b^2)(16a^2-12ab+9b^2) c. (64a-3b)(a^2+12ab+9b^2) d. (4a-3b)(16a^2+12ab+9b^2) ps the ^ button means power

Question 336005: Factor completely thankyou
64a^3-27b^3
a. (4a-3b)(16a^2+9b^2)
b. (4a+3b^2)(16a^2-12ab+9b^2)
c. (64a-3b)(a^2+12ab+9b^2)
d. (4a-3b)(16a^2+12ab+9b^2)
ps the ^ button means power ....example to the power of 3 thanks
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression.

Rewrite as . Rewrite as .

Now factor by using the difference of cubes formula. Remember the difference of cubes formula is

Multiply

-----------------------------------
Answer:
So factors to .

In other words,

So the answer is D)

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my website.

Jim
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