SOLUTION: Not sure if I'm in the right place. I am stuck on this problem, and can't find anyone who understands it.
3/y-3 - 7/y+2 + 4 = 0
If this isn't the right place, can you tell me
Algebra.Com
Question 329664: Not sure if I'm in the right place. I am stuck on this problem, and can't find anyone who understands it.
3/y-3 - 7/y+2 + 4 = 0
If this isn't the right place, can you tell me where I need to post?
Thanks so much for your help!!!
S
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
solve
:
It's an equation so we can get rid of the denominators by mult by (y-3)(y+2)
(y-3)(y+2)* - (y-3)(y+2)* + 4(y-3)(y+2) = 0
:
Cancel the denominators, FOIL
3(y+2) - 7(y-3) + 4(y^2 - y - 6) = 0
:
3y + 6 - 7y + 21 + 4y^2 - 4y - 24 = 0
:
Combine like terms, form a quadratic equation
4y^2 + 3y - 7y - 4y + 6 + 21 - 24 = 0
:
4y^2 - 8y + 3 = 0
Factor
(2y - 3)(2y - 1) = 0
Two solutions
2y = 3
y = 1.5
and
2y = 1
y = .5
:
:
Check solution using x=1.5 in the original equation
-2 - 2 + 4 = 0
:
You can check the x=.5 solution
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