SOLUTION: 6{[3(c-4)+19]-[3(2c-3)+1]}
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Question 284387: 6{[3(c-4)+19]-[3(2c-3)+1]}
Found 2 solutions by satiq, richwmiller:
Answer by satiq(1) (Show Source): You can put this solution on YOUR website!
6{[3(c-4)+19]-[3(2c-3)+1]}
6{[3c-12+19]-[6c-9+1]}
6{3c+7-[6c-8]}
6{3c+7-6c+8}
6{-3c+15}
-18c+90
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
6* { [3*(c-4)+19] - [3*(2c-3)+1] }
break it up
....3*(c-4)=3c-12
....3*(2c-3)=6c-9
6* { [3c-12+19] - [6c-9+1] }
..........- [6c-9+1]=-(6c-8)=-6c+8
6*(3c+7-6c+8)=
6*(-3c+15)=
-18c+90=
90-18c
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