SOLUTION: hi id like a break down on this question and could you please show all working and details
(n-3)(n-4)-3(n+2)(n-3)
Algebra.Com
Question 279725: hi id like a break down on this question and could you please show all working and details
(n-3)(n-4)-3(n+2)(n-3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(n-3)(n-4)-3(n+2)(n-3)
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= n^2-3n-4n+12 -3[n^2-3n+2n-6]
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= n^2 - 7n + 12 -3n^2 + 9n-6n + 18
--
= -2n^2 -4n + 30
======================
Cheers,
Stan H.
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