SOLUTION: Actually I wanted to favtorize: {{{15x^2-22x+8}}} So I multiplied 8 with 15 and got 120. The factors came as {{{-10}}} and {{{-12}}} Then I split the {{{22x}}} into these 2 num

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Question 252544: Actually I wanted to favtorize:

So I multiplied 8 with 15 and got 120.
The factors came as and
Then I split the into these 2 numbers, so I got:

Then what do I do next? Please help I have no clue!
Found 4 solutions by JimboP1977, Alan3354, Edwin McCravy, kensson:
Answer by JimboP1977(311)   (Show Source): You can put this solution on YOUR website!
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!

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It's a trial and error thing. The 1st term, 15, can be:
1*15 or 3*5
The last term, 8, can be 1*8 or 2*4. It's +8, so the signs are the same.
Start with 1 and 15, ignore the sign but try to get 22 for the middle term:
(x - 1)*(15x - 8) --> 23x NG
(3x - 1)*(5x - 8) --> 29x NG
------------------------------
(x - 2)*(15x - 4) --> 34x NG
(3x - 2)*(5x - 4) --> 22x That's it. The 22x is negative, so it's factored.
------------------------------------
The best approach is to use the quadratic equation, but students are usually subjected to factoring before learning the quadratic equation.
Answer by Edwin McCravy(20086)   (Show Source): You can put this solution on YOUR website!

Split it into a red half and a black half



Factor  out of the red half, and
factor  out of the black half.
Don't forget that since you're taking a negative
out of the  you get  not .



Do some re-coloring:



Take out the green parentheses, and that leaves the black
 and the black  in another parentheses:



That's it!

Edwin
Answer by kensson(21)   (Show Source): You can put this solution on YOUR website!
Great start!
You need to factorize the first pair of terms and the second before joining them together:
5x(3x-2) - 4(3x-2) = (5x-2)(3x-2)
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