SOLUTION: Factor completely: (5x^2 + 14x + 13)^2 - 16(x^2 + x - 2)^2
Algebra.Com
Question 252301: Factor completely: (5x^2 + 14x + 13)^2 - 16(x^2 + x - 2)^2
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This is a difference of squares:
the tricky part is to notice that 16 = 4^2. So the second term is really 4^2(X^2+x-2)^2
combine like terms within each large [stuff]
continue factoring
RELATED QUESTIONS
Factor completely. Show all work neccessary.
x^2 - 14x +... (answered by jim_thompson5910)
Factor the polynomial completely.... (answered by rfer)
factor completely x^6-14x^4+49x^2.... (answered by Alan3354)
How would I factor completely... (answered by Alan3354)
Factor... (answered by babynarah2007)
Factor... (answered by ReadingBoosters)
Factor... (answered by ReadingBoosters)
factor completely, indicate if prime... (answered by stanbon)
Factor completely: x^2 - 8x +... (answered by jim_thompson5910)