SOLUTION: Please help me solve this problem. Okay, so You have 20-x^2 evaluate. /20- x^2/ over y + 3 When X= -4

Question 220485: Please help me solve this problem.
Okay, so You have 20-x^2

evaluate. /20- x^2/ over y + 3
When X= -4
When y= -1
Found 2 solutions by Tyannrae, MathTherapy:
Answer by Tyannrae(1) (Show Source): You can put this solution on YOUR website!
Okay, so You have 20-x^2
_______
y + 3
x = -4, and -4 squared = +16, because a negative times a negative is a positive.
Remember that you have a subtraction sign after the 20, before the positive 16, so the problem on top becomes 20 - 16, which equals 4.
y = -1, so the bottom part = -1 + 3 which is the same as 3 - 1, which equals 2.
so the top of your fraction = 4, and the bottom = 2... so 4/2 = 2!
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Please help me solve this problem.
Okay, so You have 20-x^2

evaluate: , when x = -4, and y = -1

-------- =
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