# SOLUTION: i have a word problem that has me baffled, please help as this is complicated for me. There are 8 more quarters than dimes. The total money is \$6.20. How many dimes are there?

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: i have a word problem that has me baffled, please help as this is complicated for me. There are 8 more quarters than dimes. The total money is \$6.20. How many dimes are there?       Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Distributive, associative, commutative properties, FOIL Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Distributive-associative-commutative-properties Question 216324: i have a word problem that has me baffled, please help as this is complicated for me. There are 8 more quarters than dimes. The total money is \$6.20. How many dimes are there? i know the answer by trial and error is 12 dimes, but how do I put it into an equation? Thanks for your time and patience. BenAnswer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Let Q = the number of quarters and D = the number of dimes. Q = D+8 "There are 8 more quarters than dimes." Each quarter is worth \$0.25 and each dime is worth \$0.10, so... Q(0.25)+D(0.10) = \$6.20 Substitute Q = D+8. (D+8)(0.25)+D(0.10) = 6.2 0.25D+2+0.1D = 6.2 0.35D+2 = 6.2 Subtract 2 from both sides. 0.35D = 4.2 Divide both sides by 0.35 D = 12 and Q = D+8 Q = 12+8 = 20 There are 20 quarters and 12 dimes.