SOLUTION: 21x^2+2x-3= (7x+3)(3x-1) Check: (7x+3)(3x-1)=7x(3x)+7x(-1)+3(3x)+3(-1)=21x^2-7x+9x-3-21^2+2x-3

SOLUTION: 21x^2+2x-3= (7x+3)(3x-1) Check: (7x+3)(3x-1)=7x(3x)+7x(-1)+3(3x)+3(-1)=21x^2-7x+9x-3-21^2+2x-3

Algebra.Com

Question 174347: 21x^2+2x-3= (7x+3)(3x-1)
Check: (7x+3)(3x-1)=7x(3x)+7x(-1)+3(3x)+3(-1)=21x^2-7x+9x-3-21^2+2x-3
Answer by mattiewal(1) (Show Source): You can put this solution on YOUR website!
21x^2+2x-3= (7x+3)(3x-1)
Check: (7x+3)(3x-1)=7x(3x)+7x(-1)+3(3x)+3(-1)=21x^2-7x+9x-3-21^2+2x-3
RELATED QUESTIONS
subtract... (answered by MikeLomax,richwmiller)

(3x^2+2x^3)-(3x^2+7x-1) (answered by jim_thompson5910)

7x+3>2(3x+1)+4 (answered by nyc_function)

-6(3x-1)=2(3-7x)-4x (answered by rfer)

(2x-1)(3x^2-9x+6) 7x^3-14x^2+21x 7x 4x^3-15x2-190x+9 x-9 The last two... (answered by stanbon)

(x+3)/(3x-1)-(8x^2+8x+3)/(3x^2-7x+2)+(2x+3)/(x-2)=? (answered by richwmiller)

Add: (4x^3-3x+9)+(-2x^2-4)+(8x+3x^3) Subtract: (7x^2-3x+1)-(9x^2-7x-3) Thanks... (answered by Tatiana_Stebko)

multiply... (answered by fractalier)

15x^4+3x^3-7x^2/3x^2+1 (answered by Fombitz)