You can
put this solution on YOUR website!let a,b,c,d,e be 1st,2nd,3rd,4th,and 5th numbers respectively
:
e+c=14--->e+(b-10)=14--->e=-b+24..eq 1
d=b+1.............................eq 2
a=2b-1............................eq 3
b=c+10---->c=b-10.................eq 4
a+b+c+d+e=30
:
take the 1st four values e,d,a,and c from the 1st 4 equations and plug them into eq 5
:
(2b-1)+b+(b-10)+(b+1)+(-b+24)=30
:
4b+14=30
:
4b=16
:

2nd number
:

1st number
:

3rd number
:

4th number
:

5th number
You can
put this solution on YOUR website!e + c = 14 ; e + 10 - b = 14 ; e = b + 4 ; e = 4 + 4 = 8
d = b + 1 ; d = 4 + 1 = 5
a = 2b - 1 ; a = 2 (4) - 1 = 7
b + c = 10 ; c = 10 - b ; c = 10 - 4 = 6
and
a + b + c + d + e = 30
(2b - 1) + (b) + (10 - b) + (b + 1) + (b + 4) = 30 ; b = 4
check:
(2(4)-1) + (4) + (10 - 4) + (4 + 1) + (4 + 4) = 30
(7) + (4) + (6) + (5) + (8) = 30
30 = 30
a = 7; b = 4; c = 6; d = 5 and e = 8