SOLUTION: Determine the restricted value(s). x^2-4x-21/x^2+16

Question 171585: Determine the restricted value(s).
x^2-4x-21/x^2+16
Answer by monika_p(71) (Show Source): You can put this solution on YOUR website!

denominator can not be =0 (you can not divide by 0)
first lets check when x^2+16=0
x^2=-16 false ( squared number can not be equal to a negative number)
that means that all values of x from set of R (real numbers) fulfill that expression and there is no restricted values
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