SOLUTION: Determine the resticted value(s). How do I go about doing so? 8x/x-4

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Question 171484: Determine the resticted value(s). How do I go about doing so?
8x/x-4
Found 2 solutions by nerdybill, monika_p:
Answer by nerdybill(5414) About Me  (Show Source):
You can put this solution on YOUR website!
For any fraction, if the denominator is zero -- the fraction is undefined.
.
Therefore for your fraction:
+%288x%29%2F%28x-4%29+
.
The restricted value(s) of x would be when:
x-4 = 0
Solving for x:
x = 4 (this is the only restricted value)

Answer by monika_p(71) About Me  (Show Source):
You can put this solution on YOUR website!
8x/(x-4) restricted values are values of x that make denominator =0 (division by zero isn't allowed)
lets check when denominator is = 0 ----> x-4=0 that happenes when x=4
Then the restricted value is 4