You can
put this solution on YOUR website!lets call x the hypothenuse and sides a, a+1(because one side is one unit longer)
:
we know that

but we also know that P=a+a+1+x::: 12=2a+1+x
:
x=11-2a----. plug this value into the 1st equation.
:

solve for a

:

divide by 2
:

factor
:

:
x=11-2a....11-2(20)=-29 so throw that out as its a negative length
...........11-2(3)=5
so one side is 3 the other side is 4 and the hypothenuse is 5