SOLUTION: 10-x-2x^2/2x^2-9x+10
=-2x^2-x+10/2x^2-9x+10
=(2x+2)(-x+5)/(2x+2)(2x+5)
=(-x+5)/(2x+2)
Algebra.Com
Question 163637: 10-x-2x^2/2x^2-9x+10
=-2x^2-x+10/2x^2-9x+10
=(2x+2)(-x+5)/(2x+2)(2x+5)
=(-x+5)/(2x+2)
Answer by orca(409) (Show Source): You can put this solution on YOUR website!
=
=
=
=
RELATED QUESTIONS
2x^2=10-x (answered by checkley71)
2x+2(x-10) (answered by jim_thompson5910,unlockmath)
2x^2-x-10 (answered by jim_thompson5910)
-2X^2-X+10 (answered by Alan3354)
x^2+6x+10=2x+2x^2 (answered by checkley71)
9x-10 + 2x^2 + x^2+4 Triangle perimeter
(answered by checkley71)
1/2x-5=10 Given
2(1/2x-5)=2(10). [. ]
X-10=20. (answered by Cromlix)
domain of... (answered by stanbon)
Solve by factoring: f(x) = 2x^2 + 9x +... (answered by Fombitz)