SOLUTION: Im very sorry i made a error on my last question the real question is how do you get k in this equation 6(k+2)+2(2k-5)=22
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Algebra: Distributive, associative, commutative properties, FOIL
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Question 154949
:
Im very sorry i made a error on my last question the real question is how do you get k in this equation 6(k+2)+2(2k-5)=22
Answer by
oscargut(682)
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6(k+2)+2(2k-5)=22
then
6k+12+4k-10=22
then
10k+2=22
10k=20
k=2
