SOLUTION: (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)

Question 150831: (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)
Found 2 solutions by mangopeeler07, stanbon:
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
(x^2)/(x^2+3x+2) divided by (x^2+2X)/(x^2-1)

Factor everything
x(x)/(x+2)(x+1) divided by x(x+2)/(x-1)(x+1)

Cancel out all like terms
x/1 divided by 1/x-1

Flip the second fraction and multiply
x/1 multiplied by x-1

x(x-1)
x^2-x

Answer: x^2-x
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)
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Invert the denominator and multiply:
[(x^2)/(x^2+3x+2)] * [(x^2-1)/(x^2+2X)]
----------------
Factor where you can:
[(x^2)/(x+1)(x+2)] * [(x+1)(x-1)/(x(x+2)]
------------------
Cancel where you can:
[(x)/(x+2)] * [(x-1)/(x+2)]
--------------------
Simplify:
= [x(x-1)] / (x+2)^2
=========================
Cheers,
Stan H.

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