SOLUTION: find the shortest distance between the parallel lines with equations 5x-12y+33=0 and 5x-12y-6=0 A.3 B.39 c.27/5 D.27/13 E.n/a

Question 146723:
find the shortest distance between the parallel lines with equations 5x-12y+33=0 and 5x-12y-6=0
A.3
B.39
c.27/5
D.27/13
E.n/a

Found 2 solutions by jim_thompson5910, miker:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First you need to find the line that is perpendicular to (it will also be perpendicular to )

Now this line will intersect with both equations 5x-12y+33=0 and 5x-12y-6=0. So you want to find the points of intersection. From there, simply use the distance formula to find the distance between the two points of intersection. I hope that's enough to get you started.
Answer by miker(1) (Show Source): You can put this solution on YOUR website!
D=sqrtformula (x^2-x^1)^2+(y^2-y^1)^2
d= (5x^2-5x^1)^2+(-12y^2-12y^1)^2
d= (25x-5x)^2 + (144y-12y)^2
d= (20x)^2 + (132y)^2

and then this i where i get stuck

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