# SOLUTION: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9      Log On

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 Algebra: Distributive, associative, commutative properties, FOIL Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Distributive-associative-commutative-properties Question 138233: How do you solve for each variable: (x-3)(x-7)=0 b^2+3b-4=0 n^2+n-12=0 5x^2+18x=8 3a^2+4a=2a^2-2a-9Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!(x-3)(x-7)=0 x-3=0 x=3 answer x-7=0 x=7 answer. ------------------------------------- b^2+3b-4=0 (b+4)(b-1)=0 b+4=0 b=-4 answer. b-1=0 b=1 answer. ------------------------------------------------ Here's 2 solutions. I'll leave the rest of your homework for you to practice on.