SOLUTION: I was adding the algebraic fractions a/a+3 and 4/a+5. I got a^2+5a/(a+3)(a+5)+4a+12/(a+3)(a+5). I added the numerators and got a^2+9a+12, but I can't factor it. Is it possible?

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: I was adding the algebraic fractions a/a+3 and 4/a+5. I got a^2+5a/(a+3)(a+5)+4a+12/(a+3)(a+5). I added the numerators and got a^2+9a+12, but I can't factor it. Is it possible?      Log On


   

Question 135471This question is from textbook Prentice Hall New York Integrated Algebra
: I was adding the algebraic fractions a/a+3 and 4/a+5. I got a^2+5a/(a+3)(a+5)+4a+12/(a+3)(a+5). I added the numerators and got a^2+9a+12, but I can't factor it. Is it possible? This question is from textbook Prentice Hall New York Integrated Algebra

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
A^2+9A+12 CAN BE FACTORED BY USING THE QUADRATIC EQUATION:
aX^2+bX+c
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
YOU'LL GET ANSWERS OF (-1.62 & -7.37).