SOLUTION: 1/2 (m+1)(3m + 2) + (3m+4) =1/2 [(m+1)(3m+2) + ________ ] =1/2 [(m+1)(3m+2) + 6m+8] =1/2 [(m+1)(3m+2)+(3m+2)+(3m+6)] =1/2 [(m+2)(3m+2)+___________ ] =1/2 (m+2)(3m+

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Question 1194584: 1/2 (m+1)(3m + 2) + (3m+4)
=1/2 [(m+1)(3m+2) + ________ ]
=1/2 [(m+1)(3m+2) + 6m+8]
=1/2 [(m+1)(3m+2)+(3m+2)+(3m+6)]
=1/2 [(m+2)(3m+2)+___________ ]
=1/2 (m+2)(3m+5)
=1/2 [(m+1)+1][3(m+1)+2]

here are my answers
1/2 (m+1)(3m + 2) + (3m+4)
=1/2 [(m+1)(3m+2) + 2(3m+4)]
=1/2 [(m+1)(3m+2) + 6m+8]
=1/2 [(m+1)(3m+2)+(3m+2)+(3m+6)]
=1/2 [(m+2)(3m+2)+3(m+2)]
=1/2 (m+2)(3m+5)
=1/2 [(m+1)+1][3(m+1)+2]
Please help, thanks

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
you have to simplify and see which of following is simplified form
........multiply




.........factor
=> your answer
and, you already did it by your self
1/2 (m+1)(3m + 2) + (3m+4)
=1/2 [(m+1)(3m+2) + 2(3m+4)]
=1/2 [(m+1)(3m+2) + 6m+8]
=1/2 [(m+1)(3m+2)+(3m+2)+(3m+6)]
=1/2 [(m+2)(3m+2)+3(m+2)]
=-> you needed to stop here

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