# SOLUTION: Please help me with this problem. I have similar problems in my homework but it does not show how to solve this type of problem. You help is appreciated. Problem: 6y over y^2+5y+4

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: Please help me with this problem. I have similar problems in my homework but it does not show how to solve this type of problem. You help is appreciated. Problem: 6y over y^2+5y+4      Log On

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 Question 117515: Please help me with this problem. I have similar problems in my homework but it does not show how to solve this type of problem. You help is appreciated. Problem: 6y over y^2+5y+4 add to 4y over y^2-1. I tried to factor the first denominator but that just got me more confused. I don't know where to start. Found 2 solutions by solver91311, edjones:Answer by solver91311(17075)   (Show Source): You can put this solution on YOUR website! Factoring both denominators is the key to doing this problem just as you suspected. Since 4 X 1 = 4 and 4 + 1 = 5, this trinomial factors rather neatly. . Now, you can write your problem with fully factored denominators, thus: Next you need a common denominator. In this case, you have one factor of , one of , and one of , so: Next, factor the numerator Eliminate Sometimes it might be more convenient to leave your answer just like that. At least the domain of the function is readily apparent (all Reals except -4 and 1). But if need be, multiply the binomial, thus: Hope that helps, John Answer by edjones(7569)   (Show Source): You can put this solution on YOUR website!6y/(y^2+5y+4)+4y/(y^2-1) =6y/((y+4)(y+1))+4y/((y+1)(y-1)) Factor the denominators. =(6y(y-1)+4y(y+4))/((y+4)(y+1)(y-1)) LCD is the denominator =6y^2-6y+4y^2+16y/((y+4)(y+1)(y-1)) Expand the numerator. =10y^2+10y/((y+4)(y+1)(y-1)) Combine terms. = =10y/((y+4)(y-1)) Voila! . Ed