SOLUTION: find the two consecutive integers such that the square of the sum of the two integers is 11 more than the first integer.
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Question 111627This question is from textbook Beginning & intermediate algebra
: find the two consecutive integers such that the square of the sum of the two integers is 11 more than the first integer.
This question is from textbook Beginning & intermediate algebra
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
First integer - N
Next consecutive integer - N+1
The solutions are N=-5/2 and N=2
Since you require the solution to be an integer, we only accept the second solution (N=2).
Check the answer.
True statement.
Good answer.
The integers are 2 and 3.
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