SOLUTION: distibute 1000 so that one part has 3 times as large as the second one and the third has the sum of the other two

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First Part + Second Part + Third Part = 1000
First Part = 3 x Second Part
Third Part = First Part + Second Part
Let's assign a variable to each part.
X = First Part
Y = Second Part
Z = Third Part
Your original equation.
First Part = 3 x Second Part
Third Part = First Part + Second Part

Substitute for what you know, in terms of Y. \
Simplify.
Use multiplicative inverse of 8.



So then,
First Part = 125
Second Part = 375
Third Part = 500