Questions on Algebra: Distributive, associative, commutative properties, FOIL answered by real tutors!

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Question 151212This question is from textbook Intermediate Algebra
: I am having problems factoring this trinomial. The problem is 8a^2-18ay+7y^2. I would appreciate if someone could help me.
Thanks!
This question is from textbook Intermediate Algebra
: I am having problems factoring this trinomial. The problem is 8a^2-18ay+7y^2. I would appreciate if someone could help me.
Thanks!

Answer by jim_thompson5910(9401) About Me  (Show Source):
You can put this solution on YOUR website!
Looking at 8a^2-18ay+7y^2 we can see that the first term is 8a^2 and the last term is 7y^2 where the coefficients are 8 and 7 respectively.

Now multiply the first coefficient 8 and the last coefficient 7 to get 56. Now what two numbers multiply to 56 and add to the middle coefficient -18? Let's list all of the factors of 56:



Factors of 56:
1,2,4,7,8,14,28,56

-1,-2,-4,-7,-8,-14,-28,-56 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 56
1*56
2*28
4*14
7*8
(-1)*(-56)
(-2)*(-28)
(-4)*(-14)
(-7)*(-8)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to -18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -18

First NumberSecond NumberSum
1561+56=57
2282+28=30
4144+14=18
787+8=15
-1-56-1+(-56)=-57
-2-28-2+(-28)=-30
-4-14-4+(-14)=-18
-7-8-7+(-8)=-15






From this list we can see that -4 and -14 add up to -18 and multiply to 56


Now looking at the expression 8a^2-18ay+7y^2, replace -18ay with -4ay+-14ay (notice -4ay+-14ay adds up to -18ay. So it is equivalent to -18ay)

8a^2+highlight(-4ay+-14ay)+7y^2


Now let's factor 8a^2-4ay-14ay+7y^2 by grouping:


(8a^2-4ay)+(-14ay+7y^2) Group like terms


4a(2a-y)-7y(2a-y) Factor out the GCF of 4a out of the first group. Factor out the GCF of -7y out of the second group


(4a-7y)(2a-y) Since we have a common term of 2a-y, we can combine like terms

So 8a^2-4ay-14ay+7y^2 factors to (4a-7y)(2a-y)


So this also means that 8a^2-18ay+7y^2 factors to (4a-7y)(2a-y) (since 8a^2-18ay+7y^2 is equivalent to 8a^2-4ay-14ay+7y^2)



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Answer:
So 8a^2-18ay+7y^2 factors to (4a-7y)(2a-y)