Questions on Algebra: Distributive, associative, commutative properties, FOIL answered by real tutors!

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Question 150831: (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1): (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)
Answer by mangopeeler07(445) About Me  (Show Source):
You can put this solution on YOUR website!
(x^2)/(x^2+3x+2) divided by (x^2+2X)/(x^2-1)

Factor everything
x(x)/(x+2)(x+1) divided by x(x+2)/(x-1)(x+1)

Cancel out all like terms
x/1 divided by 1/x-1

Flip the second fraction and multiply
x/1 multiplied by x-1

x(x-1)
x^2-x

Answer: x^2-x
Question 150831: (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1): (x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)
Answer by stanbon(19020) About Me  (Show Source):
You can put this solution on YOUR website!
(x^2)/(x^2+3x+2)/(x^2+2X)/(x^2-1)
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Invert the denominator and multiply:
[(x^2)/(x^2+3x+2)] * [(x^2-1)/(x^2+2X)]
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Factor where you can:
[(x^2)/(x+1)(x+2)] * [(x+1)(x-1)/(x(x+2)]
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Cancel where you can:
[(x)/(x+2)] * [(x-1)/(x+2)]
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Simplify:
= [x(x-1)] / (x+2)^2
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Cheers,
Stan H.