Questions on Algebra: Distributive, associative, commutative properties, FOIL answered by real tutors!

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Question 146512This question is from textbook Algebra 1 An Incremental Development
: Multiply: (3x-5)(7x-5)This question is from textbook Algebra 1 An Incremental Development
: Multiply: (3x-5)(7x-5)
Answer by jim_thompson5910(9401) About Me  (Show Source):
You can put this solution on YOUR website!

(3x-5)(7x-5) Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


(highlight(3x)-5)(highlight(7x)-5) Multiply the First terms:(3*x)*(7*x)=21*x^2.


(highlight(3x)-5)(7x+highlight(-5)) Multiply the Outer terms:(3*x)*(-5)=-15*x.


(3x+highlight(-5))(highlight(7x)-5) Multiply the Inner terms:(-5)*(7*x)=-35*x.


(3x+highlight(-5))(7x+highlight(-5)) Multiply the Last terms:(-5)*(-5)=25.


21*x^2-15*x-35*x+25 Now collect every term to make a single expression.


21*x^2-50*x+25 Now combine like terms.


So (3x-5)(7x-5) FOILS to 21*x^2-50*x+25.


In other words, (3x-5)(7x-5)=21*x^2-50*x+25.