SOLUTION: Identify the vertex, axis of symmetry , y-intercept, x-intercepts, and opening of each parabola, then sketch the graph. f(x) = (x+1)^2

SOLUTION: Identify the vertex, axis of symmetry , y-intercept, x-intercepts, and opening of each parabola, then sketch the graph. f(x) = (x+1)^2 - 9

Question 995047: Identify the vertex, axis of symmetry , y-intercept, x-intercepts, and opening of each parabola, then sketch the graph.
f(x) = (x+1)^2 - 9
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
The parabolic function is already in standard form, so all that information asked is easy to find. Intercepts on x you solve for f(x)=0. Vertex and symmetry axis, you just read from the function definition. Leading coefficient will be , so parabola opens upward.

vertex                  (-1,-9)
axis of symmetry         x=-1
roots                   -4  and  +2
y-intercept             evaluate f(0).  y=-8 where x=0,.

You have enough information, or data, to make a sketch of the graph.
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