SOLUTION: hello, this is my homework and I couldn't find the right answer for it. I will provide the step I did to try and solve the problem. Also, I would really appreciate if you could poi

Question 990623: hello, this is my homework and I couldn't find the right answer for it. I will provide the step I did to try and solve the problem. Also, I would really appreciate if you could point out the mistake I did so I could improve.

Question:
Find the point (x,y) on the line y=−2x−3 that is equidistant from the points (−1,6) and (−2,9).
my step:
d� = (x-a)� + (x-b)�

= (x-[-1])� + (y-6)�
= x� +2x+1+y�-12y+36=x�+4x+4+y�-18y+81
2x+1-12y+36-4x-4+18y-81=0
-2x+6y-48=0
-2x+6(-2x-3)-48
-2x-12x-18-48
-14x-66
x=-66/14
y=-2x-3
= -2(66/14)-3
= -174/14

Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
You have an unknown line with general points, (x, -2x-3). This point is same distance from point (-1,6) as from point (-2,9).

Distance Formula will give the equation to express that reworded description.

Analyze that for it to all make sense. You can then continue with the algebraic steps to simplify the equation and solve for x.
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