SOLUTION: How do you write an equation in standard form that goes through the point (-4,3) and with a y-intercept of 0?

Question 985204: How do you write an equation in standard form that goes through the point (-4,3)
and with a y-intercept of 0?
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
given:
the line passes through the point (,)
and with a y-intercept of ; means the line will pass through origin (,)
so, firs we can find the equation of this line in slope-intercept form

Solved by pluggable solver: Find the equation of line going through points

hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-4, 3) and (x2, y2) = (0, 0).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(-0.75)x + (0)

Your graph:

so, the equation of this line in slope-intercept form is
the standard form for linear equations:

so, we have

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