# SOLUTION: Please Help. I am no good with graphing Solve and graph the solution set: a)5y + 3 <u><</u> -2 or y - 7 <u>></u> 0 b) x - 9 < 3x - 4 < x + 8 PLEASE HELP!!!!!!!!!

Algebra ->  Algebra  -> Coordinate-system -> SOLUTION: Please Help. I am no good with graphing Solve and graph the solution set: a)5y + 3 <u><</u> -2 or y - 7 <u>></u> 0 b) x - 9 < 3x - 4 < x + 8 PLEASE HELP!!!!!!!!!      Log On

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 Click here to see ALL problems on Coordinate-system Question 87233: Please Help. I am no good with graphing Solve and graph the solution set: a)5y + 3 < -2 or y - 7 > 0 b) x - 9 < 3x - 4 < x + 8 PLEASE HELP!!!!!!!!!Answer by Edwin McCravy(8882)   (Show Source): You can put this solution on YOUR website!```Please Help. I am no good with graphing Solve and graph the solution set: a)5y + 3 < -2 or y - 7 > 0 b) x - 9 < 3x - 4 < x + 8 PLEASE HELP!!!!!!!!! a)5y + 3 < -2 or y - 7 > 0 Solve each part: 5y + 3 < -2 or y - 7 > 0 -3 -3 +7 +7 ------------------------- 5y < -5 or y > 7 5y < -5 or y > 7 y < -1 or y > 7 Draw three number lines with a closed circle at the boundary points (closed because it's "<" and not "<"): y < -1 -----------l-------------l---------- -1 7 y > 7 -----------l-------------l---------- -1 7 y < -1 or y > 7 -----------l-------------l---------- -1 7 Shade the first one to the left of -1, because "less than" is "left": y < -1 <===========l------------l---------- -1 7 Shade the second one to the right of 7, because "greater than" is "right": y > 7 -----------l-------------l==========> -1 7 Now since the word between the inequalities is "OR" and not "AND", we shade all parts of the final number line if it is shaded on the first one OR if it is shaded on the second one. So the final number line is: y < -1 or y > 7 <============l-------------l==========> -1 7 Now we imagine that there is a "negative infinity" on the far left and an "infinity" on the far right. So the interval notation is (-oo, -1] U [7, oo) b) x - 9 < 3x - 4 < x + 8 Add -x + 9 to all three sides: x - 9 < 3x - 4 < x + 8 -x + 9 -x + 9 < -x + 9 ------------------------ 0 < 2x + 5 < 17 Add -5 to all three sides: 0 < 2x + 5 < 17 -5 -5 -5 ------------------------ -5 < 2x < 12 Divide all three sides by 2, to get only x in the middle: -2.5 < x < 6 That means -2.5 < x AND x < 6 which is the same as x > -2.5 AND x < 6 Draw three number lines with an open circle at the boundary points (open because it's ">", "<" and not "<",">: x > -2.5 -----------o-------------o---------- -2.5 6 x < 6 -----------o-------------o---------- -2.5 6 x > -2.5 and x > 6 -----------o-------------o---------- -2.5 6 Shade the first one to the right of -2.5, because "greater than" is "right": x > -2.5 -----------o========================> -2.5 6 Shade the second one to the left of 6, because "less than" is "left": x < 6 <========================o---------- -2.5 6 Now since the word between the inequalities this time is "AND" and not "OR", we shade only the parts of the final number line if it is shaded on the first one AND shaded on the second one. So the final number line shaded is: x > -2.5 and x > 6 -----------o=============o---------- -2.5 6 In interval notation that is (-2.5, 6) Edwin```