SOLUTION: How do I graph the linear equation 3x + 2y = 6 by plotting 5 points. You must choose at least one negative x value. Show the points as ordered pairs. Thanks for your help

Question 84439: How do I graph the linear equation 3x + 2y = 6 by plotting 5 points. You must choose at least one negative x value. Show the points as ordered pairs. Thanks for your help
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First, convert the the equation to slope-intercept form

Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

Start with the given equation

Subtract 3x from both sides

Simplify

Divide both sides by 2 to isolate y

Break up the fraction on the right hand side

Reduce and simplify

The original equation (standard form) is equivalent to (slope-intercept form)

The equation is in the form where is the slope and is the y intercept.

Now in order to graph , we need to plot some points.

So we can start at any x value. So lets start at x=-4

Start with the given equation

Plug in

Calculate the y value
So when

So our 1st point is (-4,9)

Start with the given equation

Plug in

Calculate the y value
So when

So our 2nd point is (-2,6)

Start with the given equation

Plug in

Calculate the y value
So when

So our 3rd point is (0,3)

Start with the given equation

Plug in

Calculate the y value
So when

So our 4th point is (2,0)

Start with the given equation

Plug in

Calculate the y value
So when

So our 5th point is (4,-3)

Start with the given equation

Plug in

Calculate the y value
So when

So our 6th point is (6,-6)

Now lets make a table of the values we have calculated

Now plot the points

Now connect the points, this is the graph of

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