SOLUTION: Find an equation(s) of the circle(s) tangent to 2x - 3y + 6 = 0 at (3,4); center on 3x + 2y

SOLUTION: Find an equation(s) of the circle(s) tangent to 2x - 3y + 6 = 0 at (3,4); center on 3x + 2y - 17 = 0

Question 835835: Find an equation(s) of the circle(s) tangent to 2x - 3y + 6 = 0 at (3,4); center on 3x + 2y - 17 = 0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find an equation(s) of the circle(s) tangent to 2x - 3y + 6 = 0 at (3,4); center on 3x + 2y - 17 = 0
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The 2 lines intersect at (3,4) --> an infinite # of circles that fit.
3x + 2y - 17 = 0
y = -3x/2 + 17/2
Pick any point on the line and find its distance from (3,4)
Use (h,k) for the point

d is the radius

y = -3x/2 + 17/2 --> k = -3h/2 + 17/2

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Pick any value for h and you get a circle that fits.

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