SOLUTION: how to find the value of k if the lines 2x-5=ky and (k+1)x=6y-3 have the same gradient. i don't know which formula should i apply can you please tell me the formulas by steps only

Question 803383: how to find the value of k if the lines 2x-5=ky and (k+1)x=6y-3 have the same gradient. i don't know which formula should i apply can you please tell me the formulas by steps only i would like to calculate it by my own self.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2x-5=ky and (k+1)x=6y-3 have same slopes

2x-5=ky
y= (2/k)x-5/k

(k+1)x=6y-3
(k+1)x+3 =6y
(k+1)/6 x +1/2 = y

the slopes of both lines are equal
2/k =(k+1)/6
12=k(k+1)
12=k^2+k
k^2+k-12=0
k^2+4k-3k-12=
k(k+4)-3(k+4)=0
(k+4)(k-3)=0
k=4 OR 3

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