SOLUTION: Okay, First off, thank you for even helping me! I truly appreciate it!Well, here's my problem.. Quadrilateral TUVW with T (-4,2) U (-2,4) V (0,2) and W(-2,-4)rotated 90 degrees cou

Question 797359: Okay, First off, thank you for even helping me! I truly appreciate it!Well, here's my problem.. Quadrilateral TUVW with T (-4,2) U (-2,4) V (0,2) and W(-2,-4)rotated 90 degrees counterclockwise about the origin.
What I don't really understand is what the Quadrilateral looks like on the graph, after the rotation, and what the coordinates are for the new rotated shape.
Thanks a MILLION and I appreciate it very much!!
Sincerely
~Maria
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Quadrilateral TUVW with T (-4,2) U (-2,4) V (0,2) and W(-2,-4)rotated 90 degrees counterclockwise about the origin.
What I don't really understand is what the Quadrilateral looks like on the graph, after the rotation, and what the coordinates are for the new rotated shape.
--------------------
It will be the same shape, just rotated.
T (-4,2) --> T' (-2,-4)
U (-2,4) --> U' (-4,-2)
V (0,2) --> V' (-2,0)
W (-2,-4) --> W' (4,-2)
=======================
The distance from the Origin remains the same after rotation.
The x & y are swapped (for 90 deg rotation). The signs are determined by the ending quadrant.
----
email via the TY note and I'll send a graph.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

So what you have is a kite shape. The easiest point to rotate through 90 degrees counterclockwise is the point that is on one of the axes, namely (0,2).

If you rotate (0,2) 90 degrees to the left, then you end up at (-2,0).

Next the original point (-2,4) is 2 units up and 2 units left of (0,2), so the rotation of (-2,4) is goint to be 2 units down and 2 units right of (-2,0) (which is the rotation of (0,2). That is: (-4,-2).

Next, the original point (-4,2) is on the horizontal line through the original point (0,2) and 4 units to the left. So the rotation of (-4,2) has to be on a vertical line with (-2,0), the rotation of (0,2), and 4 units down. That is: (-2,-4)

Let me know what you get for the position of the last point.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

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