SOLUTION: 1) find the point (x,y) on the line y=4x+5 that is equidistant from the points (-9,7) and (-8,3) 2) find the perimeter of the triangle with the vertices at (1,2), (-6,5) and (-6,-

Question 785377: 1) find the point (x,y) on the line y=4x+5 that is equidistant from the points (-9,7) and (-8,3)
2) find the perimeter of the triangle with the vertices at (1,2), (-6,5) and (-6,-3)
thank you!!!
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Question #1.

The line contains some general point, (x, 4x+5). The distance from this general point to one of the given points must be equal to the distance from the general point to the other given point. Setup the distance formula expressions.

From the line to (-9,7):

From the line to (-8,3):

These two expressions, equated and then both sides squared, give

Use the line equation again for finding y.

'
Point solution is (9/16, 29/4)
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