SOLUTION: Graph f(x)=-x^4+2

Question 78530: Graph f(x)=-x^4+2
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Graph f(x)=-x^4+2
Because the leading exponent is even and the leading cofficient is negative we know that as x goes to -infinity f(x) goes to -infinity and as x goes to positive infinity f(x) goes to -infinity.
plug in a few negative values for x and a few positive values for x and solve for f(x), which is y.
When x=-2
f(-2)=-(-2)^4+2=-16+2=-14 Plot (-2,-14)
f(-1)=-(-1)^4+2=-1+2=1 Plot (-1,1)
f(0)=-(0)^4+2=0+2=2 Plot (0,2)
f(1)=-(1)^4+2=-1+2=1 Plot (1,1)
f(2)=-(2)^4+2=-16+2=-14 Plot (2,-14)
:
Connect the dots and you have a graph.

If you're taking calculus let me know because there are other things you can do.
Happy Calculating!!!
RELATED QUESTIONS
graph f(x)= x^2 +... (answered by mathie123)

f(x)=2^-x+4... (answered by jim_thompson5910)

GRAPH... (answered by tvandenberg)

Graph f(x) +... (answered by solver91311)

graph:... (answered by checkley71)

Graph f(x) = �x �... (answered by elima)

Graph f(x) = �x �... (answered by burkus)

Graph f(x) = �x �... (answered by jim_thompson5910)