SOLUTION: find the equation of the circle centered at (3,-9) and passing throught point (1,2)
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Question 762529: find the equation of the circle centered at (3,-9) and passing throught point (1,2)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The equation of a circle centered at )
with radius 
is:
^2\ +\ (y\ -\ k)^2\ =\ r^2)
You are given the center, and the radius is the distance from the center to any point on the circle, one of which you were given.
Use the following modification of the distance formula to find the radius squared.
^2\ +\ (y_1\ -\ y_2)^2)
where )
and )
are the coordinates the given center and given point on the circle.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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